Calculating p values and degree of freedom

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**Introduction**

We calculating P value of populations with different variances

n1=62

n2=62

F-Calculated =2(current)/2(proposed)

Mean (current) = (76+76+77+…………. +66+70+74+72)/62=4579/62

**=****75.06557377**

Mean (proposed) = (74+75+77+…………. +74+72+78+71)/62=4601/62

**=****75.42622951**

Variance=1/n∑ x2-n (x‾)

1/62{(76*76+76*76+77*77+…………. +66*66+70*70+74*74+72*72)-62(75.06557377)

**=****15.56229508**

Variance (proposed) =1/62{74*74+75*75+77*77+………+74*74+72*72+78*78+71*71)-62(75.42622951)

**=****6.281967213**

F-calculated= 15.56229508/6.281967213

**=****2.477296**

**Degree of freedom **

(N1-1, n2-1)= (**61, 61)**

**CRITICAL F-VALUE** (**61, 61****) at **α=0.05

=1.52883315

Since F-calculated=2.477 is greater than F (61, 61) reject the null hypothesis.

**Conclusion**

There is sufficient evidence at α=0.05 level to conclude that the average change driven by current state of the machinery differs from average speed driven by proposed machinery.

**References**

Hedgecock, D., Chow, V., & Waples, R. S. (2012). Effective population numbers of shellfish broodstocks estimated from temporal variance in allelic frequencies. *Aquaculture*, *108*(3-4), 215-232.